Roulette rotor deceleration from your video .
0.18s is not same on 2s rotor or 6s rotor.
The proper representation should be ;
(I approximated 14s time in between measurements)
(37/3.93 - 37/3.76) /14s = (9.41 - 9.84) /14 = -0.03 pockets/s^2
An example:
Say you clocked rotor 10p/s and the ball drops after 20s.
v = u + at
v = 10p/s + (- 0.03) x 20 = 10 - 0.6 = 9.4
distance = (10+9.4)/2 x 20 = 9.7 x 20 = 194 pockets
If you use initial velocity 10p/s then rotor would make 200 pockets.
So you would have rotor in in 6 pockets different position.