I am new in vb2 and I have a simple question,it is basic, might sound silly, but I need an answer, otherwise I can not go further.
So, first time I start ball clocking from dd - lets say its 12 o clock - and after my reference time elapses, the ball will be at 3 o clock (so it makes a distance of 5 revolution quarters). The question is: in order to confirm the first predicted hit number, my next clocking will start immediately at 3 o clock or do I have to start again only when the ball will be at 12 o clock?
Thank you very much!
There is no silly question if it helps you to understand.
So, first time I start ball clocking from dd - lets say its 12 o clock - and after my reference time elapses, the ball will be at 3 o clock (so it makes a distance of 5 revolution quarters).
During your reference time the ball should make about 1.5-3 rotations.
It means the ball is about 0.6-1 sec per rotation.
With repeating reference time you do not check predicted hit number but will you get same number predicted again. If that’s clear then yes you start timing the ball at same place at 12 0 clock.
Imagine you start your reference time 14 sec to the end.
Rotor is 4 sec / per rotation
You apply reference time of 2 sec, Starting at diamond “12” (could be any not just DD) and in that time the ball makes full 3 rotations and it is over number “0”. at diamond “12”. (now is 12 sec. to the end of spin)
Now you wait and when the ball is again at diamond “12” (for example 10 sec to the end of spin) you do it once more.
Now the ball is slower, in 2 sec, it will make 2 rotations and again indicate zero, since the rotor form last 12 sec to 8 sec to the end of spin moved full rotation; zero will be again at 12.
THIS IS NOT A PREDICTION. It is just a quick test if you selected good reference time for the wheel you play and rotor speed range you going to play.
If the ball is going in clock way direction and in a second attempt instead of number “0” you get number " 2" it means your reference time needs to increase ~200-300ms.
Once you define right reference time which to use; then you can play VB2 . Based form this example it would be irrelevant did you start anywhere in between 14-10 sec to the end of spin. VB2 reference time will always correct you as you were always reading number in same remaining time to the end of spin.
VB2 is only one way of play. I developed for myself and found it the easiest to use.
1. Every ball clocking during a spin has to start from the SAME point.
Yes, you actually testing will the VB2 predict same at one moment then again few sec later.
Remember; VB2 doesn’t like to late predictions.
2. If I get the same number every time, then my reference time is correct.
Yes, of course it doesn’t have to be 100% but close so you know you are in the range.
3. What if I get number 10 at every clocking and in the end the ball hits rotor at number 20? I suppose an offset of 6 pockets must be applied. In that case, the reference time should be still correct.
Yes, the number you get after your elapsed time as an reference; in usual is not related to ball destination but it keeps the same distance. As in previous example at 12 sec to the end zero was your reference, in that case with 4 sec rotor the ball should drop somewhere around zero but that’s only an example. (12/4= 3 full rotations). If you were taking reading at 9 o clock then instead of reading 0 you would read 9-22)
4. In case that I use the offset of 6 pockets, the starting point of ball clocking has to be the same for every spin. Of course, we assume the rotor speed is the same
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So instead of adding constantly 6 pockets you just shift your starting point by 6 pockets.
Next spin if you clock rotor and in 2 sec it made 2 extra pockets. That’s 1p/s; you can shift your starting point by additional 12 pockets. It also means for each Y amount of pocket that rotor makes extra or less you add od deduct Y x 6 pockets. You can add it after prediction or you can just shift your starting point. That’s if you were predicting about 12 sec to the end of spin and time is 2 sec.
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