Hi.

Is there anybody that could please tell me what is the probability of winning 132 units in 96 spins assuming it is a 100% random roulette wheel? Betting 20 numbers on each spin.

Thanks!

Well i assume you are asking the probability to win 132 units or more? Winning exactly 132 units is

96Choose57 x (20/37)^(57) x (17/37)^39

=0.04763148873

If you win, you win 16 units, if you loose you loose 20units.

Inorder to win 132units, you have to win exactly 57

Spins and loose 39 spins as 57x16 - 20x39=132 units. The 96Choose57 comes from the combinations of this winning 57spins and losing 39spins happening.

If you wanna do winning 132 units or more for a random wheel,

Lets do the maths, lets assume european wheel

Probability of winning is 20/37

Probability of losing is 17/37

Assume you bet 20 units on each spin, 1unit on each of the 20 numbers,

When you win, it is +16units

When you loose, it is -20units

Winning 132 units in 96 spins, we can do a calculation using the above.

Hint: using binomial

Lets assume n=amount of times you win and 96-n the amount of times you loose.

16n+(-20)x(96-n)>=132

n>=57

Therefore, you have to win 57times or more and at the same time lose 39times or less. You just have to add this formula,

N Choose R × (20/37)^(R)x(17/37)^(N-R)

For R of values 57 all the way up to 96

Hey there! The probability of winning 132 units in 96 spins on a 100% random roulette wheel, betting 20 numbers each time, would depend on the specific odds of each bet. It’s a bit complex, but you’d need to calculate the odds of winning for each spin and then figure out the overall probability ...

Well the probability of winning is just 20/37 and loosing is 17/37 for a random wheel.